Program 5

Question

4: Design a Shell Program that takes any number of arguments and prints them in the same order and in reverse order with suitable messages.

Code

#!/bin/sh

if [ $# -eq 0 ]; then
    echo "No arguments"
else
    echo "Number of arguments: $#"
    echo "The input arguments are"
    num=1
    for arg in "$@"; do
        echo "arg$num is $arg"
        num=$(expr $num + 1)
    done
    echo "Arguments in reverse order"
    num=$#
    while [ $num -ne 0 ]; do
        eval "echo arg$num is $$num"
        num=$(expr $num - 1)
    done
fi

Output

$ sh rev.sh A B C
Program name: rev.sh
Number of arguments: 3
The input arguments are
arg1 is A
arg2 is B
arg3 is C
Arguments in reverse order
arg3 is C
arg2 is B
arg1 is A

Summary

This script accepts any number of arguments and prints them in the same order and in reverse order. It showcases argument handling, counting, and reversing the order.